My lead acid batteries are brand new. The manufacturer supplies a value of 0.33mOhm of internal resistance when a battery is fully charged at 25°C.
We are talking about a 12x2=24v battery bank. So let’s forget about the cables connecting the batteries (2x70mm2 BTW) and assume a total resistance of 12x0.33mOhm = 3,96mOhm
Under an absorption voltage of 28,8v at 25ºC how much tail current should one theoretically expect when SOC=100%?
Does anyone know the proper math?