I am looking for the short-circuit current (ISC) that can be delivered by a MultiPlus 6K5 inverter in island mode.
Out of curiosity what are you using the information for?
For the undocumented inverters it is sort of “traditionally”…
20C deg
2 x Inom - 0,5Sec ( when the load is so high the inverter isn’t able to maintain AC voltage as in short circuit situations)
2 x Inom - 2 min when the Ac voltage is as it should be
1,3 x Inom - 30min
The tech specs refer to Time-limited power (cold start) fugures
The inverter will shut down if a load higher than its max output (over x seconds) is drawn which is what a short circuit on the output should do to it.(Overload shut down)
It seems 11k over 1 minute is the rating in the tech specs, so if you sizing a fuse on the output rate it for the amps there. (47A so 50 amps since that’s the closest size unless you want to size down?)
If a breaker keep to the inom as breakers allows way over current before tripping.
According to the Dutch code (nen1010), in the event of a short circuit the circuit breakers must trip within 0.2 seconds.
For this, a current of 3×In to 5×In is required for a B‑characteristic breaker.
For a 16‑ampere breaker, this means 48 to 80 amperes.
According to the AUS datasheet, a 48/48000 inverter can deliver 80A short‑circuit current.
However, this inverter is far too oversized for the rest of my usage.
And could not find any information for the 6K5.
I guess a 6k5 should be able to deliver enough current for a B10 breaker and but maybe not enough for a 16A breaker.
It will switch off due to overload, that will take longer than 0.2s but the voltage in that time will be almost 0V → safe.
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If the voltage will drop in 0,2, that will also be confom code.
I have to go for the 8K of perhaps the 10k